Is an automatic system possible?

Two coils in a loose coupling (the third is the adapter only)

between the current flows backwards.Only in some cases. This will result in a decrease in power supply current.
This can be clearly seen at 40 seconds:

https://www.youtube.com/watch?v=2RzUMWZ6ZBg&t=1s

The reactive current of the capacitor between the two coils fluctuates in both directions. (we know what will happen if currents and magnetic fields of the same magnitude and direction meet! We also know that a coil can be primary or secondary. Depending on where the current is going)
This can be seen on an external LED indicator (8:20) This phenomenon only exists under load. The load wire resistance (i.e. linear) and D.C. you get tension.
The direction of flow can be clearly seen on the current meter built into the power supply. Charging and then discharging. Here (finally in each arrangement) this phenomenon occurs when the two magnetic fields meet. In this case, the primary coil becomes secondary. So the energy flows back to the power supply.
It's like a swing.

https://www.youtube.com/watch?v=_SXzp9ZGAXg&t=1s

Some more thoughts on the M.E.G. device. Comments by T.Bearden:

-By shaping the leading edge and trailing edge of the nearly rectangular input pulses we use to input to the primary coil around the core, we can determine the magnitude of the produced E-fields in space surrounding the core.

-However, from the SECOND energy reservoir, we also simultaneously get an input E-field reaction directly from the surrounding space and into that secondary coil. In short, if we carefully time and phase everything by -"adroit switching"- , we can get more energy into that output coil from the E-field in surrounding space, than we get into it from the H-flux inside the core.

-The decisive signature is the deviation of the normal 90 degrees or so phase difference between output voltage and output current. We can produce a "supertransformer" where that phase difference may be as small as two degrees.

Well, we know full well that M.E.G. the device is not designed to be a normal transformer. This is why the input drive coils also differ from the normal excitation. The output load is a varistor (or fluorescent which is a negative resistor, that's an important thing!) Which in some cases means a very strong capacitive load. So reactive energy. (The A_B effect is probably just theory, but not proven by anyone)

Now compare the M.E.G. device with the operation of the ferroresonance transformer. Examine both devices. (an old microwave transformer is suitable for this purpose)
The apparent (or reactive) energy will be at least 3-4 times the input energy at a frequency corresponding to an FR transformer. But only if the shunt is in place. (shunt corresponds to a permanent magnet)
When saturated the iron exits the air in flux. This is the M.E.G. device. But the same can be seen in the E.r. also in the videos at the LED indicator.Here I tried to get around the topic thoroughly. The text is not important, the pictures tell a story.
With the FR transformer, the flux cannot escape into the air so easily because it closes through the intervening shunt. So we will have two magnetic fields! And the two magnetic fields know well how they will affect each other.
I gained similar experience during the construction and testing of other permanent magnetic devices. (Árpád Bóday M.D.G generator CA002172240A does not accidentally use two transformers!, Bulgarian incomp generator)
A pm. space is very small, so the capacitor resonant circuit (reactive) amplifies.

In this arrangement, in this space, energy recharging takes place during the course already outlined above. This is already a very significant energy.

I can't say more yet.
Atti.