Beyond Unity - Non Linear Resonance

Jagau posted this 14 December 2023

I transferred my thread on Non Linear Resonance here to BeyondUnity.org

beyond-unity nonlinear resonance

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Jagau posted this 3 days ago - Last Edited 3 days ago

Atti made a very good replication,

tell me apart from him,

are there others who succeeded??

Jagau

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Jagau posted this 5 weeks ago

These are excellent videos Atti, thank you for sharing them.
We can see on the third the same effect as the disruptive discharge of a capacitor, excellent.
Jagau

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Atti posted this 07 April 2024

Quoting:Jagau

Quote from Gerry Vassitalos in his book of ''LOST SCIENCE''

The "primary" and "secondary" of Tesla Transformers are not magnetic inductors.

They are coil-shaped capacitors! Tesla Transformer action is electrostatic induction.

One of Tesla's biggest well-kept secrets.

Jagau

Hi eveione.

Unfortunately, at this moment I cannot contribute to confirm the results of the experiment. But I will try.
My experiments with coil-shaped capacitors confirm Jagau's statements.
You may have already seen experiments on these (if you asked or not)
Just one example:

Atti.

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Jagau posted this 15 February 2024 - Last Edited 16 February 2024

Nice demonstration Atti thank you

And excellent comment Yoelmicro.

@Atti
Now as promised, you can double the power collected by adding another AV plug and charging another capacitor, right here where I placed the red arrow, at the junction of the two pulsed coils.

You will now have two well charged capacitors, be careful a lot of voltage here.

You will double your voltage at the output with the two charged capacitors as you did with the first without increasing the power at the input. This is the advantage of an open system on a single wire. You master the current experiment very well, my congratulations, thank you.

We see at the end of the video that the input power increases greatly due to the standard transformer effect by using the two wires at the output, nice demonstration.

Jagau

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YoElMiCrO posted this 15 February 2024

Hello everyone.

@Atti.

Yes, that's real, but remember that it's the average that's important.
Let me explain...
The real problem is that to load a cap to 1J you need a
longer than the discharge time, then in the ideal case
that you don't have any losses the energy is the same view from
the source that in the load..
That's a COP of 1.
The same goes for inductors, for example...
Imagine an inductor that has 100 turns and peak current
at 1A, this is 100A/Turn.
If the secondary has one turn, and you apply a 1 Ohm load to it
the peak voltage is 100V, if the resistor is 10 Ohm then
you will have 1000V, but you have to remember that the voltage that is reflected
to the primary in the first case is 10000V+ Edc and in the second case...
The other thing is that di/dt=VL/L and the time it takes to rise to 1A
will be larger than the magnetic energy discharge, but the average
It's the same if the system is ideal.

YoElMiCrO.

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Atti posted this 15 February 2024

Hello everyone.

This is just a manual test. There is no timing circuit.
A sudden discharge of energy stored in the capacitor can cause a problem in an improperly selected mosfet. Or a switching element.
Think about it. The energy stored in the capacitor.
If 1 J of work is done in 1 s, you get 1 W of power.
But if you do 1 J of work in 1 ms, you get 1 kW of power.
And if 1 J of work is done in 1 µs, you get 1 MW of power.
And so on.
This reminds me of thyristor ignition.
Given the right parameters, using spark gap is also interesting for non-inductive primary drive. As I mentioned above.
Instead of a timing circuit, another usable variant. In my opinion.

Atti.

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Jagau posted this 11 February 2024 - Last Edited 11 February 2024

How to make power calculation with capacitor, so the energy expended to stored joules in a capacitor.

quoting Yoelmicro

You're right, power is energy per frequency (Ef) or energy between time (E / t)
as well as voltage per DC current.

So the energy expended to produce 550V in a 7uF capacitor is ...
EIt = 5 * 0.019 * 2.5 = 0.2375 joules.

and Yoelmicro gave here an exemple how to calculate:

Let's calculate the energy stored in the capacitor ...
E = Vc ^ 2C / 2 = (550 ^ 2 * 7 * 10 ^ -6) / 2 = 1.05875 joules.

The energy efficiency is Eout / Ein = 1.05875 / 0.2375 = 4.4579.
Corroborating your calculations.

So i think it will help lot of us to get correct calculation about capacitor calculation and joules stored.

Jagau

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Jagau posted this 10 February 2024

Yes, it’s completely normal Atti, you should not place a charge immediately at output. You must charge the NP capacitor before discharging it into a small 120volts lamp, after about 3 seconds you should have between 350 and 500vdc depending on the capacity of your capacitor,i used 7UF NPcap, and we calculate the power in volts/second like yoelmicro suggest it.

There are different ways to do a capacitor dump, the simplest is manually and the other is with a comparator LM339. If you want a model I can show it to you here.

For example in this comparator you can change the reference voltage with a R2 100k variable to adjust the discharge voltage required in your circuit or use a mosfet at the output.

more delails here

https://www.ermicro.com/blog/?p=1578

When you have mastered this part, I will tell you how to double your output power, good experimentation Atti

Jagau

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Atti posted this 10 February 2024

Hi Jagau.

Yes, I tried it. The single wire system (AV plug) doesn't work so well for me. As soon as I put the load on the diode/capacitor output the voltage drops. I used values of 100ohm, 1K,10K, for the load. The voltage drops below one volt. Connecting a ground to the other end of the output wire does not improve the output voltage magnitude.
Interesting fact.
If I try to apply a load to the output wires in a conventional way, at some point the primary current drawn from the power supply drops. This load is a small light bulb. However, it does not light up.
Only when I use a spark plug (so it arcs).
I think that is when capacitive reactance compensation takes place. There is current, no voltage. Or correction.
But even so, the energy level is weak.
For now.

Atti.

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Jagau posted this 10 February 2024

Hello Atti
Have you tried an AV plug on a single wire at the output and measured the voltage?

Jagau

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